WAEC - Physics (2010 - No. 37)
Determine the potential difference. V across the parallel resistors
2.0V
2.3V
3.0V
0.7V
Explanation
6Ω and 4Ω are parallel.
\(\frac{1}{R_T}\) = \(\frac{1}{R_1} + \frac{1}{R_2}\)
\(\frac{1}{R_T}\) = \(\frac{1}{6} + \frac{1}{4}\)
\(R_T\) = \(\frac{12}{5}\) = 0.97Ω
V = IR
= 0.97 x 2.4 = 2.3V
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