WAEC - Physics (2010 - No. 36)
0.60A
0.97A
1.03A
5.00A
Explanation
\(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}\)
= \(\frac{1}{6} + \frac{1}{4}\)
R = \(\frac{12}{5} = 2.5\Omega\)
R = 2.4 + 10 = 12.4
V = IR
I = \(\frac{v}{R} = \frac{12}{12.4} = 0.97\)
= \(\frac{1}{6} + \frac{1}{4}\)
R = \(\frac{12}{5} = 2.5\Omega\)
R = 2.4 + 10 = 12.4
V = IR
I = \(\frac{v}{R} = \frac{12}{12.4} = 0.97\)
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