WAEC - Physics (2010 - No. 28)
From the diagram, the correct equation for the refractive index n of the medium is
n = tan i
n = \(\frac{sin i}{sin 90^o}\)
n = \(\frac{sin i}{cos (90^o - i)}\)
n = sin 90oC
Explanation
refractive index(n) = \(\frac{sin i}{sinr}\)
where r = 180-(90+i) ā r=90-i
since sin(90-i)=cos i
: refractive index(n) = \(\frac{sin i}{cos i}\)
ā tan i
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