WAEC - Physics (2009 - No. 14)
A machine of efficiency 80% is used to lift a box. If the effort applied by the machine is twice the weight of the box. Calculate the velocity ratio of the machine
0.50
0.63
0.80
1.60
Explanation
Y = \(\frac{M.A}{V.R} \times \frac{100}{1}\)
= \(\frac{\frac{1}{2}}{V.R} \times \frac{100}{1}\)
V.R = 0.625
= \(\frac{\frac{1}{2}}{V.R} \times \frac{100}{1}\)
V.R = 0.625
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