WAEC - Physics (2008 - No. 5)
A car travelling with a uniform velocity of 30ms-1 along a horizontal road overcomes a constant frictional force of 600N. Calculate the power of the engine of the car
18kW
20kW
180kW
200kW
Explanation
P = FV
= 600 x 30 = 18kW
= 600 x 30 = 18kW
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