WAEC - Physics (2007 - No. 13)

An external force of magnitude 100N acts on a particle of mass 0.15kg for 0.03s. Calculate the change in the speed of the particle
50ms-1
25ms-1
20ms-1
5ms-1

Explanation

a = \(\frac{F}{m} = \frac{100}{0.15} = 666.7\)

v = u + at

= 0 + 66.7 x 0.03

= 20m/s2

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