WAEC - Physics (2005 - No. 26)
The distance between two points in phase on a progressive wave is 5cm. If the sped of the wave is 0.2ms-1, calculate its period
4.00s
2.50s
0.25s
0.04s
Explanation
F = \(\frac{v}{\lambda} = \frac{0.2}{5 \times 10^{-2}} = 4Hz\)
T = \(\frac{1}{f} = \frac{1}{4} = 0.25s\)
T = \(\frac{1}{f} = \frac{1}{4} = 0.25s\)
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