WAEC - Physics (2004 - No. 41)
Calculate the energy stored in a 20\(\mu F\) capacitor. If the p.d between the plates is 40V
3.2 x 10-2J
1.6 x 10-2J
8.0 x 10-4J
4.0 x 10-4J
Explanation
W = \(\frac{cv^2}{2} = \frac{20 \times 10^{-6} \times 40^{2}}{2}\)
= 1.6 x 10-2J
= 1.6 x 10-2J
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