WAEC - Physics (2002 - No. 27)

The refractive index of a medium relative to air is 1.8. Calculate to the nearest degree, the critical angle for the medium
68o
56o
34o
18o

Explanation

c = \(\sin^{-1} \frac{1}{n} = \sin^{-1} \frac{1}{1.8} = 34^o\)

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