Sign In

WAEC - Physics (2002 - No. 13)

In the diagram above, AB represents a uniform rod of length 1.50m which is in equilibrium on a pivot at P, If AP = 40cm, calculate the mass of the rod. [g = 10ms-2]
0.280kg
0.400kg
0.613kg
0.800kg

Explanation

m = \(\frac{0.7 \times 40}{35} = 0.8kg\)

Comments (0)

Advertisement