WAEC - Physics (2000 - No. 48)
A proton of wavelength \(\lambda_o\) is emitted when an electron in an atom makes a transition from a level of energy 2E. If the electron transits from \(\frac{4}{3}E_k\) to E level, determine the wavelength of the photon that would be emitted
3\(\lambda_o\)
2\(\lambda_o\)
\(\frac{3}{4}\)\(\lambda_o\)
\(\frac{1}{3}\)\(\lambda_o\)
Explanation
2E - E = \(\frac{hc}{\lambda}\) = E = \(\frac{hc}{\lambda}\)
\(\frac{4}{3}\)E = \(\frac{hc}{\lambda_{new}}\)
E = \(\frac{3hc}{\lambda_2}\)
\(\frac{3hc}{\lambda_2}\) = \(\frac{hc}{\lambda}\)
\(\lambda_{new}\) = 3 \(\lambda_o\)
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