WAEC - Physics (2000 - No. 15)

A machine of efficiency 80% is used to raise a body of mass 75kg through a vertical height of 3m in 30s. Calculate the power input. (g = 10ms-2)
9.4W
60.0W
75.0W
93.8W

Explanation

Efficiency = \(\frac{ poweroutput}{powerinput}\)

but power output = \(\frac{ f \times s}{ t}\) = \(\frac{75 \times 10 \times 3}{ 30}\) = 75W

Efficiency = 80%, power output = 75w

then 0.8 =  \(\frac{ 75}{powerinput}\)

power input =  \(\frac{ 75}{0.8}\) = 93.75W.

Comments (0)

Advertisement