WAEC - Physics (1999 - No. 38)

A 10 Ω coil takes 21 s to melt 10g of ice at 0ºC. Assuming no heat losses, determine the current in the coil. (Specific latent heat of fusion of ice = 336 Jg\(^{-1}\))

16A

Explanation

Heat lost = Heat used to melt ice

I\(^2\)R t = mL

I\(^2\) x 10 x 21 = 10 x 336

I\(^2\) = \(\frac{3360}{210}\) = 16

I = \(\sqrt{16}\) = 4A.

WAEC - Physics (1999 - No. 38)

Explanation

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