WAEC - Physics (1998 - No. 35)
Calculate he wavelength of a note which is one octave lower than a note of 256Hz in a medium in which the speed of sound is 352ms-1
0.69m
1.38m
2.75m
5.50m
9.30m
Explanation
\(\lambda\) = \(\frac{v}{f} = \frac{352}{256}\)
= 1.38
= 1.38
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