WAEC - Physics (1998 - No. 12)
An object is heated from 30ºC to 57ºC. The increases in its temperature on the Kelvin scale is
17k
27k
81k
246k
300k
Explanation
30°C + 273 = 303K
57°C + 273 = 330K
∆T = 330K - 303K
→ 27K
Comments (0)
30°C + 273 = 303K
57°C + 273 = 330K
∆T = 330K - 303K
→ 27K
