WAEC - Physics (1996 - No. 4)
A ball of mass 5.0kg hits a smooth vertical wall normally with a speed of 2ms-1 and rebounds with the same speed. Determine the impulse experienced by the ball
20.0kg ms-1
10.0kg ms-1
5.0kg ms-1
1.3kg ms-1
0.0kg ms-1.
Explanation
Impulse = Ft = mu - (-mu)
= mu + mu = 2mu = 2 x 5 x 2 = 20kgms-1
= mu + mu = 2mu = 2 x 5 x 2 = 20kgms-1
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