WAEC - Physics (1996 - No. 12)
Two simple pendula x and y make 400 and 500 oscillations respectively in equal time. If the period of oscillation of x is 1.5 seconds, what is the period of oscillation of y?
0.53s
0.83s
1.20s
1.50s
1.88s.
Explanation
where f = \(\frac{oscillations}{time}\)
period = 1/ f or \(\frac{time}{oscillations}\)
For pendulum x:
where period = 1.5 and oscillation = 400
time = oscillations X 1.5 = 600s
For pendulum y:
\(\frac{time}{oscillations}\) → 600/500
period for y = 1.2s
period =
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