WAEC - Physics (1995 - No. 41)
If the current in the resistor R in diagram above is 0.05A, calculate the p.d. across the inductor.
2.5V
25.0V
49.0V
50.0V
250.0V
Explanation
V= i × \(_l\)
X\(_l\) = inductive reactance → 50
I = current → 0.05A
V = 0.05 × 50
V = 2.5volt
X\(_l\) = inductive reactance → 50
I = current → 0.05A
V = 0.05 × 50
V = 2.5volt
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