WAEC - Physics (1993 - No. 9)

An object is projected with a velocity of 100 ms\(^{-1}\) from the ground level at an angle \(\theta\) to the vertical. If the total time of flight of the projectile is 10 s, calculate θ. (g = 10 ms\(^{-2}\)).

0^o

30^o

45^o

60^o

90^o

Explanation

T = \(\frac{2u sin θ}{g}\)

sin θ = \(\frac{Tg}{2u}\)

sin θ = \(\frac{10 \times 10}{2 \times 100}\) = 0.5
θ = sin\(^{- 0.5}\) = 30º

\(\theta\)\(_{horizontal}\) = 30º

But \(\theta\)\(_{vertical}\) = 90º - 30º = 60º

WAEC - Physics (1993 - No. 9)

Explanation

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