WAEC - Physics (1993 - No. 45) | ExamPlay

WAEC - Physics (1993 - No. 45)

Calculate the current, I in the diagram shown above.
(Neglect the internal resistance of the cell)

4.0A

2.0A

1.0A

O.5A

0.1A.

Explanation

R = 2 + 2 = 4 Ω; 1/R = ¼ + ¼ = 2/4; R = 2Ω
∴ I = V/R = 2/2 = 1A

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