WAEC - Physics (1993 - No. 41)

A particle of charge 5C moves perpendicularly to a magnetic Held of magnitude C.01 T. If the velocity of the charge is 1.5ms'2, calculate the magnitude of the force exerted on the particle
0.050 N
0.075N
0.0300N
3.300N
0.000N

Explanation

F = eV = 0.01 x 5 x 1.5 = 0.075N

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