WAEC - Physics (1991 - No. 37)

A man standing 300m away from the wall sounds a whistle. The echo from the wall reaches him 1.8sec. later, calculate the velocity of sound in air
540.0ms-1
333.3ms-1
270.0ms-1
166.7ms-1
83.3ms-1

Explanation

V = \(\frac{2x}{t} = \frac{2 \times 300}{1.8}\)


= 333.33ms-1

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