WAEC - Physics (1990 - No. 10)

An object R leaves a platform XY with a horizontal velocity of 7m-1 and lands at Q. lf it takes the same object 0.3s to fall freely from Y to P, calculate the distance PQ.(Take g = 1Oms2)
7.30m
2.55m
2.10m
1.65m
0.45m.

Explanation

D = v x t = 7 x 0.3 = 2.1m

Comments (0)

Advertisement