WAEC - Mathematics (2024 - No. 42)
A die is tossed once. Find the probability of getting a prime number.
\(\frac{1}{2}\)
\(\frac{1}{6}\)
\(\frac{1}{3}\)
\(\frac{2}{3}\)
Explanation
Sample space = { 1, 2, 3, 4, 5, 6}
Prime numbers = ( 2, 3, and 5)
Pr(prime Nos) = \(\frac{\text{number of required outcome}}{\text{total possible outcome}} = \(\frac{3}{6}\) = \(\frac{1}{2}\)
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