WAEC - Mathematics (2024 - No. 25)
Given that P is 25 m on a bearing of 330º from Q, how far south of P is Q?
25.2 m
21.7 m
19.8 m
18.5 m
Explanation
Sin 60º = \(\frac{d}{25}\)
d = Sin 60º x 25 = 21.6506m ≈ 21.7m
Comments (0)
Sin 60º = \(\frac{d}{25}\)
d = Sin 60º x 25 = 21.6506m ≈ 21.7m
