WAEC - Mathematics (2024 - No. 12)

If 3x - 2y = - 5 and x + 2y = 9, find the value of \(\frac{x - y}{x + y}\)
\(\frac{5}{3}\)
\(\frac{3}{5}\)
\(\frac{-3}{5}\)
\(\frac{-5}{3}\)

Explanation

Solving 3x - 2y = -5 and x + 2y = 9 simultaneously using elimination method

3x - 2y = - 5 ----------- (i)

x + 2y = 9 ----------- (ii)

4x = 4

x = 1

put x = 1 into eqn ---(ii)

x + 2y = 9 becomes  1 + 2y = 9

2y = 9 - 1 = 8

y = \(\frac{8}{2}\) = 4

x = 1 and y = 4

Therefore, \(\frac{x - y}{x + y}\) = \(\frac{1 - 4}{1 + 4}\) = \(\frac{- 3}{5}\)

 

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