WAEC - Mathematics (2024 - No. 12)
If 3x - 2y = - 5 and x + 2y = 9, find the value of \(\frac{x - y}{x + y}\)
\(\frac{5}{3}\)
\(\frac{3}{5}\)
\(\frac{-3}{5}\)
\(\frac{-5}{3}\)
Explanation
Solving 3x - 2y = -5 and x + 2y = 9 simultaneously using elimination method
3x - 2y = - 5 ----------- (i)
x + 2y = 9 ----------- (ii)
4x = 4
x = 1
put x = 1 into eqn ---(ii)
x + 2y = 9 becomes 1 + 2y = 9
2y = 9 - 1 = 8
y = \(\frac{8}{2}\) = 4
x = 1 and y = 4
Therefore, \(\frac{x - y}{x + y}\) = \(\frac{1 - 4}{1 + 4}\) = \(\frac{- 3}{5}\)
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