WAEC - Mathematics (2023 - No. 18)
The radius and height of a solid cylinder is 8 cm and 14 cm respectively. Find, correct to two d.p the total surface area.
(Take \(\pi = \frac{22}{7})\)
(Take \(\pi = \frac{22}{7})\)
\(1,106.29cm^2\)
\(1,016.29cm^2\)
\(1,106.89cm^2\)
\(1,206.27cm^2\)
Explanation
radius = 8cm , height = 14cm and \(\pi = \frac{22}{7}\)
total surface area of a solid cylinder =\( 2πrh+2πr^2\) = 2πr( h + r )
\( 2 \times \frac{22}{7} \times 8( 8 + 14)\)
\( 2 \times \frac{22}{7} \times 8 \times 22\)
\(\frac{7744}{7}\)
= \(1,106.29cm^2\)
Comments (0)
