WAEC - Mathematics (2021 - No. 32)

 A cyclist moved at a speed of Xkm/h for 2 hours. He then increased his speed by 2 km/h for the next 3 hours.

If the total distance covered is 36 km, calculate his initials speed.

12km/h
3km/h
4km/h
6km/h

Explanation

Speed = \(\frac{\text{Distance}}{\text{Time}}\)

From the first statement, speed = xkm/h, t = 2hrs

Therefore, distance = 2xkm

From the second statement, speed = x + 2 ( since speed increased by 2km/h) and t = 3hrs

distance = 3 X (x + 2) = 3x + 6

But total distance = 36km(given)

Total distance = 2x + 3x + 6 = 36 i.e. (dist. from the first statement + dist. from the second statement)

5x + 6 = 36

5x = 36 - 6 = 30 

x = (initial speed) = \(\frac{30}{5}\) = 6Km/h

check = total distance = 36 = 2x + 3x + 6 = 12 + 18 + 6 = 36.

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