(11\(_{two}\))\(^2\) = (11\(_2\) \(\times\) (11\(_2\))

= \({1 \times 2^1 + 1 \times 2^0} \times ({1 \times 2^1 + 1 \times 2^0})\) 

= \({1 \times 2 + 1 \times 1} \times ({1 \times 2 + 1 \times 1})\)

= \({2 + 1} \times ({2 + 1})\)

= 3 \(\times\) 3 

= 9\(_{10}\) or

1001\(_2\) from