WAEC - Mathematics (2021 - No. 16)

make u the subject in x =\(\frac{2u-3}{3u + 2}\)

u = \(\frac{2x + 3}{3x - 2}\)

u = \(\frac{2x - 3}{3x - 2}\)

u = \(\frac{2x + 3}{2 - 3x}\)

u = \(\frac{2x + 3}{3x + 2}\)

x =\(\frac{2u-3}{3u + 2}\)

cross multiply

x(3u + 2) = 2u - 3

3ux + 2x = 2u - 3

collect like terms of u

2x + 3 = 2u - 3ux

\(\frac{2x + 3}{2 - 3x}\) = u