012 + 01 = 01

101\(_2\) + 12\(_y\) = 23\(_5\)

1 x 2\(^o\) + 0 x 2\(^o\) + 1 x2\(^2\) + 1 x y\(^o\) + 2 x y\(^1\) = 3 x 5\(^o\) + 3 x 5\(^1\)

1 + 4 + 1 + 2y = 3 + 15

6 + 2y = 18 

2y = 18 - 6

\(\frac{2y}{2} = \frac{12}{2}\)

y = 6