WAEC - Mathematics (2020 - No. 29)

In the diagram, \(\overline{MN}\)//\(\overline{PQ}\), < MNP = 2x, and < NPQ = (3x - 50)°. Find the value of < NPQ

200\(^o\)

100\(^o\)

120\(^o\)

90\(^o\)

2x = 3x - 50 alternate angle

50\(^o\) = 3x - 2x

50\(^o\) = x

< NPQ = (3x - 50)\(^o\)

= 3(50)\(^o\) - 50

= 150 - 50 = 100\(^o\)