WAEC - Mathematics (2020 - No. 15)
Given that x is directly proportional to y and inversely proportional to Z, x = 15 when y = 10 and Z = 4, find the equation connecting x, y and z
x = \(\frac{6y}{z}\)
x = \(\frac{12y}{z}\)
x = \(\frac{3y}{z}\)
x = \(\frac{3y}{2z}\)
Explanation
\(x\) x \(\frac{y}{z}\)
x = \(\frac{ky}{z}\)
15 = \(\frac{10k}{4}\)
\(\frac{60}{10}\) = k = 6
Therefore; x = \(\frac{6y}{z}\)
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