WAEC - Mathematics (2019 - No. 36)
If tan x = \(\frac{3}{4}\), 0 < x < 90\(^o\), evaluate \(\frac{\cos x}{2 sin x}\)
\(\frac{8}{3}\)
\(\frac{3}{2}\)
\(\frac{4}{3}\)
\(\frac{2}{3}\)
Explanation
y\(^2\) = 3\(^2\) + 4\(^2\)
y\(^2\) = 9 + 16
y = \(\sqrt{25}\)
= 5
\(\frac{\cos x}{2 \sin x} = \frac{4}{5} + 2 \times \frac{3}{5}\)
= \(\frac{4}{5} \times \frac{5}{6}\)
= \(\frac{2}{3}\)
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