WAEC - Mathematics (2019 - No. 12)

H varies directly as p and inversely as the square of y. If H = 1, p = 8 and y = 2, find H in terms of p and y.

H = \(\frac{p}{4y^2}\)

H = \(\frac{2p}{y^2}\)

H = \(\frac{p}{2y^2}\)

H = \(\frac{p}{y^2}\)

H \(\propto\) \(\frac{p}{y^2}\)

H = \(\frac{pk}{y^2}\)

1 = \(\frac{8k}{2^2}\)

k = \(\frac{4}{8}\)

= \(\frac{1}{2}\)

H = \(\frac{p}{2y^2}\)