WAEC - Mathematics (2018 - No. 4)

Find the value of x for which \(32_{four} = 22_x\)

 

three
five
six
seven

Explanation

\(32_4 = 22_x\)

\(3 \times 4^1 + 2 \times 4^o\) = \(2 \times x^1 + 2 \times x^o\)

12 + 2 x 1 = 2x + 2 x 1

14 = 2x + 2

14 - 2 = 2x

12 = 2x

x = \(\frac{12}{2}\)

x = 6

 

 

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