WAEC - Mathematics (2018 - No. 20)

The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at random scored at most 3 goals.

\(\frac{3}{25}\)
\(\frac{1}{5}\)
\(\frac{6}{25}\)
\(\frac{2}{5}\)

Explanation

No. of teams that scored at most 3 goals = 3 + 1 + 6 = 10

Hence, probability that a team selected at random scored at most 3 goals

= \(\frac{10}{25}\) = \(\frac{2}{5}\)

Comments (0)

Advertisement