WAEC - Mathematics (2018 - No. 19)
The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at randon scored either 4 or 7 goals.
\(\frac{9}{25}\)
\(\frac{1}{5}\)
\(\frac{6}{25}\)
\(\frac{2}{5}\)
Explanation
Prob. (team scored 4 goals) = Prob. (team scored 7 goals) = \(\frac{3}{25}\)
Hence, probability that a team selected at random scored either 4 or 7 goals;
= \(\frac{6}{25} + \frac{3}{25}\)
= \(\frac{9}{25}\)
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