WAEC - Mathematics (2017 - No. 39)
The diagram shows a circle O. If < ZYW = 33\(^o\) , find < ZWX
33\(^o\)
57\(^o\)
90\(^o\)
100\(^o\)
Explanation
In <WZX = 90\(^o\) < subtends In a semi O
<ZXW = 33º <s in same segment
<ZWX = 180º - (90\(^o\) + 33º)
= 57º
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