WAEC - Mathematics (2016 - No. 35)

The diagram, MOPQ is a trapezium with QP||MO, MQ||NP, NQ||OP, |QP| = 9cm and the height of \(\Delta\) QNP = 6cm, calculate the area of the trapezium.

96cm²

90cm²

81cm²

27cm²

Explanation

Area of \(\Delta\) QNP = \(\frac{1}{2} \times 9 \times 6 \) = 27cm²

Area of \(\Delta\) QMN = Area of \(\Delta\) QNP

= Area of \(\Delta\) PNO (triangles between the same parallels)

Hence, area of the trapezium

3 x area of \(\Delta\) QNP

= 3 x 27

= 81cm²

WAEC - Mathematics (2016 - No. 35)

Explanation

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