WAEC - Mathematics (2015 - No. 19)

In the diagram, O is the centre, \(\bar{RT}\) is a diameter, < PQT = 33\(^o\) and < TOS = 76\(^o\). Using the diagram, find the size of angle PRS.

76^o

71^o

38^o

33^o

In the diagram, < TRS = \(\frac{76^o}{2}\) = 38\(^o\)

Hence, angle PRS = 33\(^o\) + 38\(^o\)

= 71\(^o\)