WAEC - Mathematics (2015 - No. 10)
If m = 4, n = 9 and r = 16., evaluate \(\frac{m}{n}\) - 1\(\frac{7}{9}\) + \(\frac{n}{r}\)
1\(\frac{5}{16}\)
1\(\frac{1}{16}\)
\(\frac{5}{16}\)
- \(\frac{37}{48}\)
Explanation
If m = 4, n = 9, r = 16,
then \(\frac{m}{n}\) - 1\(\frac{7}{9}\) + \(\frac{n}{r}\)
= \(\frac{4}{9}\) - \(\frac{16}{9}\) + \(\frac{9}{16}\)
= \(\frac{64 - 256 + 81}{144}\)
= \(\frac{-111}{144}\)
= - \(\frac{37}{48}\)
then \(\frac{m}{n}\) - 1\(\frac{7}{9}\) + \(\frac{n}{r}\)
= \(\frac{4}{9}\) - \(\frac{16}{9}\) + \(\frac{9}{16}\)
= \(\frac{64 - 256 + 81}{144}\)
= \(\frac{-111}{144}\)
= - \(\frac{37}{48}\)
Comments (0)
