WAEC - Mathematics (2014 - No. 34)
Each exterior angle of a polygon is 30o. Calculate the sum of the interior angles
540o
720o
1080o
1800o
Explanation
number of sides = \(\frac{360^o}{\theta} = \frac{360^o}{306o}\)
n = 12o
Sum of interior angle = (n - 2) 180o
(12 - 2) 180v = 10 x 180o
= 1800o
n = 12o
Sum of interior angle = (n - 2) 180o
(12 - 2) 180v = 10 x 180o
= 1800o
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