WAEC - Mathematics (2012 - No. 21)
Which of these statements about y = \(\sqrt{8m}\) is correct?
log y = log 8 x log \(\sqrt{m}\)
log y = 3 log 2 x \(\frac{1}{2}\) log m
log y = 3 log 2 - \(\frac{1}{2}\) log m
log y = \(\frac{3}{2}\) log 2 + \(\frac{1}{2}\) log m
Explanation
y = \(\sqrt{8m}\); log y = log \(\sqrt{8m}\)
log y = log \(\sqrt{8}\) + log \(\sqrt{m}\)
log y = \(\frac{1}{2}\)log 2\(^3\) + log m\(\frac{1}{2}\)
log y = \(\frac{3}{2}\) log 2 + \(\frac{1}{2}\) log m
log y = log \(\sqrt{8}\) + log \(\sqrt{m}\)
log y = \(\frac{1}{2}\)log 2\(^3\) + log m\(\frac{1}{2}\)
log y = \(\frac{3}{2}\) log 2 + \(\frac{1}{2}\) log m
Comments (0)
