WAEC - Mathematics (2011 - No. 2)
Solve for x in the equation; \(\frac{3}{5}\)(2x - 1) = \(\frac{1}{4}\)(5x - 3)
zero
1
2
3
Explanation
\(\frac{3}{5}\)(2x - 1) = \(\frac{1}{4}\)(5x - 3)
\(\frac{6x}{5} - \frac{3}{5} = \frac{5x}{4} - \frac{3}{4}\)
\(\frac{6x}{5} - \frac{5x}{4} = \frac{3}{5} - \frac{3}{4}\)
\(\frac{24x - 25x}{20} = \frac{12 - 15}{20}\)
\(\frac{-x}{20} = \frac{-3}{20}\)
-20x = -60
x = \(\frac{-60}{-20}\)
x = 3
\(\frac{6x}{5} - \frac{3}{5} = \frac{5x}{4} - \frac{3}{4}\)
\(\frac{6x}{5} - \frac{5x}{4} = \frac{3}{5} - \frac{3}{4}\)
\(\frac{24x - 25x}{20} = \frac{12 - 15}{20}\)
\(\frac{-x}{20} = \frac{-3}{20}\)
-20x = -60
x = \(\frac{-60}{-20}\)
x = 3
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