WAEC - Mathematics (2010 - No. 41)

In the diagram, < ROS = 66^o and < POQ = 3x. some construction lines are shown. Calculate the value of x.

10^o

11^o

22^o

35^o

From the diagram, OP bisects < ROS

< POS = \(\frac{1}{2}\) < ROS = \(\frac{1}{2}\) x 66^o

3x = 33^o

x = \(\frac{33^o}{3}\)

= 11^o