WAEC - Mathematics (2010 - No. 39)

In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75^o. Find the value of y

105^o

110^o

130^o

150^o

Explanation

In \(\bigtriangleup\) PQR,

Q = S = 75^o (Corresponding angle)

R = Q = 75^o (Base angles of an isosceles \(\bigtriangleup\))

But, y + 75^o = 180^o (Sum of angles in a straight line)

y = 180 - 75

y = 105^o

WAEC - Mathematics (2010 - No. 39)

Explanation

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