WAEC - Mathematics (2009 - No. 36)

In the diagram, /TP/ = 12cm and it is 6cm from O, the centre of the circle, Calculate < TOP

120^o

90^o

60^o

45^o

Tan \(\theta = \frac{6}{6} = 1\)

\(\theta\) = tab - 1(1) = 45^o

< top = 20

= 2 x 45^o = 90^o