WAEC - Mathematics (2008 - No. 34)

In the diagram, < QPR = 90^o. If q² = 25 - r². Find the value of p

Given q² = 25 - r².....(1)

from Pythagoras theorem

p² = q² + r²....(2)

put(1) into (2)

p² = 25 - r² + r²

p² = 25

p = \(\sqrt{25}\)