WAEC - Mathematics (2007 - No. 58)

In the diagram, |SP| = |SR| and < PRS = 50^o. Calculate < PQR

120^o

110^o

100^o

80^o

Explanation

< PRS = RPS = 50^o (base of isosceles)

RPS = 50^o; < RSP + < PRS + < RPS = 180(sum of < s in a triangle)

< RPS + 50 + 50 = 180

< RSP = 180 - 100 = 80

then < PQR + < RSp = 180 (opp. < S of cyclic quad.)

< PQR + 80 = 180^o

< PQR = 180 - 80

= 100

WAEC - Mathematics (2007 - No. 58)

Explanation

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